Copies a block of memory from a location to another
Syntax
Usage
[result =] fb_memmove( dst, src, bytes )
Parameters
dst
starting address of destination memory
src
starting address of source memory
bytes
number of bytes to copy
Return Value
The starting address of destination memory is returned.
Description
fb_memmove copies a given number of bytes from the memory location
src to the memory location
dst. Each starting address is taken from a reference to a variable or array element.
Copying takes place as if an intermediate buffer were used, allowing the destination and source areas to overlap in any way (safer approach, and for any platform). Using
Fb_Memcopy is sufficient (and may induce greater speed) when the memory areas do not overlap.
To avoid overflows, the valid memory areas pointed to by both
src and
dst must be at least equal in size to the number of bytes to be copied.
The underlying type of the objects pointed to by both the source and destination pointers are irrelevant for this function.
The function does not check for any terminating null character in the source area. It always copies exactly the given number of bytes.
The result is a binary copy of the data.
Note: In order to copy from/to memory referenced by a
Pointer, it must be dereferenced first (or else specify in argument term the
ByVal keyword in front of the pointer name). Otherwise,
fb_memmove will try to copy the bytes from/to the
pointer variable's memory location.
Example
Dim As ZString * 33 z = "memmove can be very useful......"
Print z
fb_memmove(z[20], z[15], 11)
Print z
Sleep
Output:
memmove can be very useful......
memmove can be very very useful.
Version
Differences from QB
- The behavior and usage is new to FreeBASIC.
See also