The syntax for declaring the
References and
Using them instead of pointers.
Preamble:
The different syntaxes used to declare a reference all use the 'Byref' keyword.
Since a pointer is a variable, it is possible to modify its contents, and the same pointer can allow successive access to different variables. The association between a reference and the object that it designates is, however, fixed when it is declared.
The 'Byref' keyword indicates a variable that is declared by reference. It is used in three different contexts:
- In a procedure signature, to pass an argument by reference (byref parameter).
- In a function signature, to return a variable to the caller by reference (byref return).
- In the body of the code, to define a reference variable (byref variable).
Table of Contents
1. Passing parameter by reference to procedure (byref parameter)
{Sub|Function} procedure_name (ByRef parameter As [Const] datatype, ...
When used in the parameter list of a procedure, the
Byref keyword indicates that an argument is passed by reference, not by value. The consequence is that any modification made to the argument in the called procedure is reflected in the body of the call.
If the procedure does not need or must not to modify the transmitted object, the
Const qualifier can be used in the declaration (before the declaration of the
datatype) so that the compiler checks in the body of the procedure that the passed object is not modified in any place (otherwise, a compiler error message is issued).
- Full syntax example for passing a parameter by reference:
Declare Sub passbyref (ByRef ref As Double, ByVal value As Double) '' declaration for passing by reference
Dim As Double X = 0
Print X
passbyref(X, 1.23)
Print X
Sleep
Sub passbyref (ByRef ref As Double, ByVal value As Double) '' declaration for passing by reference
ref = value
End Sub
Output:
Note: A pointer can be passed directly (without first dereferencing it) to
Byref procedure parameter if in argument term the
Byval keyword is specified in front of the pointer name.
2. Returning variable by reference from function (byref return)
Function function_name (...) ByRef As [Const] datatype
When used in the return type of a function, the
Byref keyword indicates that the variable is returned by reference, not by value. The consequence is that the caller can modify the variable returned by the function and the modification is reflected in the state of the variable that the function processes.
If the caller does not need or must not to modify the transmitted object, the
Const qualifier can be used in the declaration (before the declaration of the
datatype) so that the compiler checks in the body of the caller that the returned object is not modified in any place (otherwise, a compiler error message is issued).
Operators (member or global), when used as functions, have also the capability to return results by reference, by using the similar syntax.
- Full syntax example for returning a variable by reference:
Declare Function returnbyref () ByRef As Double '' declaration for returning by reference
Print returnbyref()
returnbyref() = 4.56
Print returnbyref()
Sleep
Function returnbyref () ByRef As Double '' declaration for returning by reference
Static As Double X = 0
Return X
End Function
Output:
0
4.56
As for the arguments list, it should always be surrounded with parentheses even if empty.
Specific syntax:
On the left-hand side of an assignment expression using the '=' symbol, the result of the function (returned by reference) must be enclosed in parentheses when the function calls one single argument, in order to solve the parsing ambiguity.
From fbc version 0.90, '=>' can be used for assignments, in place of '=', same as for initializers, allowing to avoid parsing ambiguity (without parentheses):
Declare Function transitbyref( ByRef _s As String ) ByRef As String
Dim As String s
s = "abcd"
Print s
'' the enclosing parentheses are required here.
( transitbyref( s ) ) = transitbyref( s ) & "efgh"
Print s
'' the enclosing parentheses are not required here.
transitbyref( s ) => transitbyref( s ) & "ijkl"
Print s
Sleep
Function transitbyref( ByRef _s As String ) ByRef As String
'' This var-len string will transit by reference (input and output), no copy will be created.
Return _s
End Function
Output:
abcd
abcdefgh
abcdefghijkl
Note: A pointer can be returned directly (without first dereferencing it) for a
Byref function return if in
identifier= or
Function= or
Return statement the
Byval keyword is specified in front of the pointer name.
3. Defining reference variable in code (byref variable)
or
Unlike pointers, the reference variable must be assigned as soon as the declaration using an initializer.
datatype must be the same type as that of the variable, or a compatible type (for example one from the types of its Bases in case of inheritance):
- Only when the two types are identical (or using the second syntax with
Var), a reference variable can be considered as an alias of the variable. One can do the same operations through such a reference variable as one can do with the original variable.
- Otherwise (types compatible but not identical), one can not do all same operations than with the original variable:
For example, a base type reference variable referring to a derived type object allows to activate polymorphism when a virtual method is called on it, similarly to a base type pointer referring to a derived type object. One can do the same operations through such a reference variable as one can do with a dereferenced pointer of same type (but for both not the same operations as using directly the derived type instance).
If the code does not need or must not to modify the referred object, the
Const qualifier can be used in the declaration (before the declaration of the
data_type in the first syntax) so that the compiler checks in the code that the object is not modified, through the reference variable, in any place (otherwise, a compiler error message is issued).
There is no interaction between the life of a reference and the life of the object who is referred (similarly to a pointer: destroy an object does not destroy its pointer(s)).
Once created, each one lives his life independently.
- Full syntax example for defining a reference variable in code:
Dim As Double X = 0
Dim ByRef As Double refX = X '' declaration for defining a reference
Print X
refX = 7.89
Print X
Sleep
Output:
4. References versus pointers by comparative examples
- Function returning the greater variable between two integer variables:
- Using pointers (by passing/returning pointer variables):
Function maxPtr (ByVal p1 As Integer Ptr, ByVal p2 As Integer Ptr) As Integer Ptr
If *p1 > *p2 Then
Return p1
Else
Return p2
End If
End Function
Dim As Integer i1 = 1, i2 = 2
Print i1, i2
*maxPtr(@i1, @i2) = 3
Print i1, i2
Sleep
Output:
- Using references (by passing/returning reference variables):
Function maxRef (ByRef r1 As Integer, ByRef r2 As Integer) ByRef As Integer
If r1 > r2 Then
Return r1
Else
Return r2
End If
End Function
Dim As Integer i1 = 1, i2 = 2
Print i1, i2
maxRef(i1, i2) = 3
Print i1, i2
Sleep
Output:
- Inheritance structure with overriding subroutine and overriding function with covariant return:
- Using pointers to objects:
Type myBase Extends Object
Declare Virtual Function clone () As myBase Ptr
Declare Virtual Sub Destroy ()
End Type
Function myBase.clone () As myBase Ptr
Dim As myBase Ptr pp = New myBase(This)
Print "myBase.clone() As myBase Ptr", pp
Function = pp
End Function
Sub myBase.Destroy ()
Print "myBase.Destroy()", , @This
Delete @This
End Sub
Type myDerived Extends myBase
Declare Function clone () As myDerived Ptr Override '' overriding member function with covariant return
Declare Sub Destroy () Override '' overriding member subroutine
End Type
Function myDerived.clone () As myDerived Ptr '' overriding member function with covariant return
Dim As myDerived Ptr pc = New myDerived(This)
Print "myDerived.clone() As myDerived Ptr", pc
Function = pc
End Function
Sub myDerived.Destroy () '' overriding member subroutine
Print "myDerived.Destroy()", , @This
Delete @This
End Sub
Dim As myDerived c
Dim As myBase Ptr ppc = @c '' base type pointer to derived object c
Dim As myDerived Ptr pcc = @c '' derived type pointer to derived object c
Dim As myBase Ptr ppc1 = ppc->clone() '' base type pointer to clone of object c
' (through its base type pointer and polymorphism)
Dim As myDerived Ptr pcc1 = pcc->clone() '' derived type pointer to derived object c
' (through its derived type pointer and covariance of return value)
Print
ppc1->Destroy() '' using base type pointer and polymorphism
pcc1->Destroy() '' using derived type pointer
Sleep
Output example:
myDerived.clone() As myDerived Ptr 4663904
myDerived.clone() As myDerived Ptr 4663952
myDerived.Destroy() 4663904
myDerived.Destroy() 4663952
- Using references to objects:
Type myBase Extends Object
Declare Virtual Function clone () ByRef As myBase
Declare Virtual Sub Destroy ()
End Type
Function myBase.clone () ByRef As myBase
Dim As myBase Ptr pp = New myBase(This)
Print "myBase.clone() Byref As myBase", pp
Function = *pp
End Function
Sub myBase.Destroy ()
Print "myBase.Destroy()", , @This
Delete @This
End Sub
Type myDerived Extends myBase
Declare Function clone () ByRef As myDerived Override '' overriding member function with covariant return
Declare Sub Destroy () Override '' overriding member subroutine
End Type
Function myDerived.clone () ByRef As myDerived '' overriding member function with covariant return
Dim As myDerived Ptr pc = New myDerived(This)
Print "myDerived.clone() Byref As myDerived", pc
Function = *pc
End Function
Sub myDerived.Destroy () '' overriding member subroutine
Print "myDerived.Destroy()", , @This
Delete @This
End Sub
Dim As myDerived c
Dim ByRef As myBase rpc = c '' base type reference to derived object c
Dim ByRef As myDerived rcc = c '' derived type reference to derived object c
Dim ByRef As myBase rpc1 = rpc.clone() '' base type reference to clone of object c
' (through its base type reference and polymorphism)
Dim ByRef As myDerived rcc1 = rcc.clone() '' derived type reference to derived object c
' (through its derived type reference and covariance of return value)
Print
rpc1.Destroy() '' using base typpe reference and polymorphism
rcc1.Destroy() '' using derived type reference
Sleep
Output example:
myDerived.clone() Byref As myDerived 9775712
myDerived.clone() Byref As myDerived 9775760
myDerived.Destroy() 9775712
myDerived.Destroy() 9775760
5. Hacking on usage of references with the additional syntaxes allowed by FreeBASIC
In FB, a reference is implemented under the hood through an internal pointer which holds the address of the variable.
The access to this internal pointer is presently allowed for user, in read, and also in write for a reference variable (unlike many other languages):
- Therefore, the address of the referred variable (the value of the internal pointer) can be get by using the '@' operator applied on the reference variable symbol name:
- And even, a reference variable can be reassigned (by modifying the value of the internal pointer) to refer to another variable (of compatible type) by doing:
- The address of the internal pointer of a reference variable can even be obtained:
internal_pointer_address = @@ref
Note:
- A reference variable can also be re-initialized to a "null" reference:
- A reference variable can even be directly declared as a "null" reference:
Thus, by always using the same reference symbol name, one can mix the pure syntax on the reference with the syntax on its internal pointer.
- Example of hacking on reference symbol name:
Declare Function resizeZstring (ByRef refZstring As ZString, ByVal length As Integer) ByRef As ZString
Declare Sub prntZstring (ByRef refZstring As ZString)
Dim ByRef As ZString refZ = *CPtr(ZString Ptr, 0) '' "null" reference declaration
Const cz1 = "FB"
@refZ = @(resizeZstring(refZ, Len(cz1))) '' reference (re-)inititialization
refZ = cz1
prntZstring(refZ)
Const cz2 = "FreeBASIC"
@refZ = @(resizeZstring(refZ, Len(cz2))) '' reference re-inititialization
refZ = cz2
prntZstring(refZ)
Const cz3 = "FreeBASIC 1.06.0"
@refZ = @(resizeZstring(refZ, Len(cz3))) '' reference re-inititialization
refZ = cz3
prntZstring(refZ)
Const cz4 = ""
@refZ = @(resizeZstring(refZ, Len(cz4))) '' reference re-inititialization to "null" reference
refZ = cz4
prntZstring(refZ)
Sleep
Function resizeZstring (ByRef refZstring As ZString, ByVal length As Integer) ByRef As ZString
If length > 0 Then
If @refZstring = 0 Then
Print "Zstring memory buffer allocation"
Else
Print "Zstring memory buffer re-allocation"
End If
length += 1
Else
Print "Zstring memory buffer de-allocation"
End If
' Return *Cptr(Zstring Ptr, Reallocate(@refZstring, length * Sizeof(Zstring)))
' '' Using the "Return Byval ..." syntax allows to avoid casting + dereferencing as above
Return ByVal Reallocate(@refZstring, length * SizeOf(ZString))
End Function
Sub prntZstring (ByRef refZstring As ZString)
Print " " & @refZstring, "'" & refZstring & "'"
Print
End Sub
Output example:
Zstring memory buffer allocation
9513600 'FB'
Zstring memory buffer re-allocation
9513600 'FreeBASIC'
Zstring memory buffer re-allocation
9513600 'FreeBASIC 1.06.0'
Zstring memory buffer de-allocation
0 ''
See also